y= x^2 -2x -3 is given, to solve 2x^2 -6x -3 =0, what straight line should be added in order to solve the equation?
1.make the equation contains =0 to be like the y=... equation. NOT VICE VERSA.
x^2 -3x-3/2 =0
2.duel with the y= equation, substitute the line equation into y so that it becomes the treated
equation in procedure 1
x^2 -2x -3 = x -3/2
The equation of the line is y= x -3/2.
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